Math, asked by CAnonymousV, 11 months ago

If (3,0),(2,a) and (b,6) are the vertices of a triangle ABC whose centroid is (2,5).Find the values of a and b.

Answers

Answered by bediharsiddak
5

Answer:

9,1

Step-by-step explanation:

\displaystyle \text{Centroid is given by } \left(\frac{x_1 + x_2 + x_3 }{3}, \frac{y_1 + y_2 + y_3 }{3}\right)\\\\\therefore \frac{3+2+b}{3} = 2,  \frac{0+a+6}{3} = 5

On solving we get a = 9 and b = 1.

Answered by pulakmath007
2

The value of a = 9 , b = 1

Given :

(3,0),(2,a) and (b,6) are the vertices of a triangle ABC whose centroid is (2,5).

To find :

The values of a and b.

Formula :

If ( x₁ , y₁) , (x₂ , y₂) & (x₃ , y₃) are three vertices of a triangle then the centroid of the triangle is given by

 \displaystyle \sf{ \bigg( \frac{x_1  + x_2+ x_3}{3}  , \frac{y_1  + y_2+y_3}{3} \bigg)}

Solution :

Step 1 of 2 :

Form the equation to find the value of a and b

Here it is given that (3,0),(2,a) and (b,6) are the vertices of a triangle ABC

∴ The centroid of the triangle is

\displaystyle \sf{  = \bigg( \frac{3 + 2 + b}{3}  , \frac{0 + a + 6}{3} \bigg)}

\displaystyle \sf{  = \bigg( \frac{ b + 5}{3}  , \frac{ a + 6}{3} \bigg)}

By the given condition

\displaystyle \sf{  \bigg( \frac{ b + 5}{3}  , \frac{ a + 6}{3} \bigg) = (2, 5)}

Thus we get

\displaystyle \sf{   \frac{ b + 5}{3}  = 2 \:  \:  \: and \:  \:  \frac{ a + 6}{3}  = 5}

Step 2 of 2 :

Find the value of a and b

\displaystyle \sf{   \frac{ b + 53}  = 2 \:  \:  \: and \:  \:  \frac{ a + 6}{3}  = 5}

Now ,

\displaystyle \sf{   \frac{ b + 5}{3}  = 2}

\displaystyle \sf{  \implies \: b = 6 - 5}

\displaystyle \sf{  \implies \: b = 1}

Again ,

\displaystyle \sf{  \frac{ a + 6}{3}  = 5}

\displaystyle \sf{ \implies a + 6  = 15}

\displaystyle \sf{ \implies a = 15 - 6}

\displaystyle \sf{ \implies a = 9}

Hence the required value of a = 9 , b = 1

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