If (3,1) is the point of intersection of lines ax+by=7 and bx+ay=5, find the value of a and b.
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Sumanmi:
I think you have miscopied the question
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since x=3 and y=1
substituting their values
3a+b=7. i
3b+a=5. ii
adding we get
4a+4b=12
a+b=3. iii
subtracting we get
2a-2b=2
a-b=1. iv
adding eqn iii and iv
2a=4
a=2
substituting
2-b=1
b=1
Ans=a=2,b=1
hope it helps
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