Question

If (3/10)^3 +(1/5)^3 -(1/2)^3= 9x/1000, then find them value of x

Answer 1

the value of x is -10

Answer 2

Hope u like my process
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${( \frac{3}{10} )}^{3} + {( \frac{1}{5}) }^{3} - {( \frac{1}{2}) }^{3} = \frac{9x}{1000} \\ \\ or. \: \: {( \frac{3}{5 \times 2} )}^{3} + {( \frac{1}{5} )}^{3} - {( \frac{1}{2}) }^{3} = \frac{9x}{ {10}^{3} } \\ \\ or. \: \: (\frac{ {3}^{3} }{ {5}^{3} \times {2}^{3} } + \frac{1}{ {5}^{3} } - \frac{1}{ {2}^{3} } ) \times {5 }^{3} \times {2}^{3} = \frac{9x}{ {5}^{3} \times {2}^{3} } \times {5}^{3} \times {2}^{3} \\ (multiplying \: both \: sides \: by \: {5}^{3} \: and \: {2}^{3} ) \\ \\ or. \: {3}^{3} + {2}^{3} - {5}^{3} = 9x \\ \\ or. \: \: 9x = 27 + 8 - 125 \\ \\ or. \: 9x = - 90 \\ \\ or. \: \: x = - 10$
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