Question

if ( √3-√2-√1)(√3+√2+√1) = a√3+ b√2+ c√1 then find the value of (a+b+c) ​

Answer 1

Answer:

Given a=

3−2

2

1

=

9−8

3+2

2

=3+2

2

[on rationalizing]

b=

3+2

2

1

=

9−8

3−2

2

=3−2

2

now a

3

+b

3

=(a+b)

3

−3ab(a+b)

=(3+2

2

+3−2

2

)

2

−3(3+2

2

)(3−2

2

)[3+2

2

+3−2

2

]

=(6)

3

−3(9−8)[6]

=216 - 18

[a

3

+b

3

=198]

Here value of [a

3

+b

3

=198]