Math, asked by Sukhchani, 1 year ago

if √3 + √2 ÷ √3 - √2 = a-b √6 , find the values of a and b​

Answers

Answered by mswSwathi
163

The answer will be 5+2√6 = a - b√6

a= 5

b=-2

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ranjanakaupranjana: thank you so much!!!
Answered by JackelineCasarez
25

The values are:

a = 5

b = -2

Step-by-step explanation:

Given that,

\frac{\sqrt{3} + \sqrt{2} }{\sqrt{3} - \sqrt{2} } = a - b \sqrt{6}

by conjugating the given equation, we get

\frac{\sqrt{3} + \sqrt{2} }{\sqrt{3} - \sqrt{2} }  * \frac{\sqrt{3} + \sqrt{2} }{\sqrt{3} + \sqrt{2}}

= \frac{(\sqrt{3} + \sqrt{2})^2 }{(\sqrt{3})^2 - (\sqrt{2})^2  }

= \frac{3 + 2 + 2\sqrt{3} \sqrt{2} }{3 - 2}

= \frac{5+2\sqrt{6}}{1}

So,

\frac{5+2\sqrt{6}}{1} = a - b√6

∵ a = 5

b = -2

Learn more: Find the values

brainly.in/question/17520931

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