If 3/2 moles of oxygen combine with Al to formAl2O3,the weight of Al used in the reaction is
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the weight of Al is 54 g per mile of Al2o3
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Answer:
Explanation:
Reaction as under:
4Al + 3O2 → 2Al2O3
So stoichiometric coefficient of Al =4 and O2=3
No of moles of Al/4 =no of moles of oxygen/3
No of moles of aluminium= 3/2÷3×4
Therefore, no of moles of aluminium = 2
Mass of aluminium= 2× 27= 54
Hope this helps!
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