Question

If (3 – 3 + 22

)

4n+3 + (2 + 3 – 32

)

4n+3 + (–3 + 2 + 32

)

4n+3 = 0, then possible value of n is​

Answer 1

Answer:

• 4n+3=0. 4n=0-3. 4n=3. n=3/4