if (3/4)^2x+4 = (4/3)^x-1, find x
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(3/4)^2x+4 = (4/3)^x-1
(3/4)^2x+4 = (3/4)^-(x-1)
Bases are equal. Exponents must be equal.
2x+4 = -(x-1)
2x+4 = -x+1
2x+x = 1-4
3x = -3
x = -3/3
x = -1
Hope it helps
(3/4)^2x+4 = (3/4)^-(x-1)
Bases are equal. Exponents must be equal.
2x+4 = -(x-1)
2x+4 = -x+1
2x+x = 1-4
3x = -3
x = -3/3
x = -1
Hope it helps
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