Math, asked by wwwbijosh77, 1 year ago

if (3/4)^6 * (16/9)^5 =(4/3)^x+2, find the value of x


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AMAYTRIPATHI: amay mani tripathi
AMAYTRIPATHI: ur?

Answers

Answered by pulakmath007
28

\displaystyle \sf{  { \bigg( \frac{3}{4}  \bigg)}^{6}  \times  { \bigg( \frac{16}{9}  \bigg)}^{5} =  { \bigg( \frac{4}{3}  \bigg)}^{x + 2}  } \: then \:  \: x =2

Given :

\displaystyle \sf{  { \bigg( \frac{3}{4}  \bigg)}^{6}  \times  { \bigg( \frac{16}{9}  \bigg)}^{5} =  { \bigg( \frac{4}{3}  \bigg)}^{x + 2}  }

To find : The value of x

Solution :

\displaystyle \sf{  { \bigg( \frac{3}{4}  \bigg)}^{6}  \times  { \bigg( \frac{16}{9}  \bigg)}^{5} =  { \bigg( \frac{4}{3}  \bigg)}^{x + 2}  }

\displaystyle \sf{  \implies  \bigg({{ \bigg( \frac{4}{3}  \bigg)}^{ - 1} \bigg) }^{  6}  \times  { \bigg({ \bigg( \frac{4}{3}  \bigg) }^{2} \bigg) }^{5} =  { \bigg( \frac{4}{3}  \bigg)}^{x + 2}  }

\displaystyle \sf{  \implies  {{ \bigg( \frac{4}{3} } \bigg) }^{  -  6}  \times  { \bigg({ \frac{4}{3}  \bigg) } }^{10} =  { \bigg( \frac{4}{3}  \bigg)}^{x + 2}  }

\displaystyle \sf{  \implies  {{ \bigg( \frac{4}{3} } \bigg) }^{ 10 -  6}  =  { \bigg( \frac{4}{3}  \bigg)}^{x + 2}  }

\displaystyle \sf{  \implies  {{ \bigg( \frac{4}{3} } \bigg) }^{ 4}  =  { \bigg( \frac{4}{3}  \bigg)}^{x + 2}  }

\displaystyle \sf{  \implies  {{ \bigg( \frac{4}{3} } \bigg) }^{ x + 2}  =  { \bigg( \frac{4}{3}  \bigg)}^{4}  }

\displaystyle \sf{  \implies  x + 2 = 4  }

\displaystyle \sf{  \implies  x= 2}

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Answered by ssikeplays
2

Answer:

2

Step-by-step explanation:

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