if 3/5 of a no. exceeds its 2/7 by 44, find the no.?
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Let the number be a
3/5th of the number = 3/5×a = 3a/5
2/7th of the number = 2/7×a = 2a/7
According to the question,
3/5 of a number exceeds its 2/7 by 44
3a/5 - 2a/7 = 44
(21a-10a)/35 = 44
11a = 44×35
11a = 1540
a = 1540/11
a = 140
Therefore,the number is 140.
Hope it helps
3/5th of the number = 3/5×a = 3a/5
2/7th of the number = 2/7×a = 2a/7
According to the question,
3/5 of a number exceeds its 2/7 by 44
3a/5 - 2a/7 = 44
(21a-10a)/35 = 44
11a = 44×35
11a = 1540
a = 1540/11
a = 140
Therefore,the number is 140.
Hope it helps
saaloni:
I can't understand
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