Question

Of the three angles of a triangle, the second is one third the first and the third is 26 degree more than the first find the measure of all the angles

Answer 1

A +B+C=180
B=1/3×A
C=26+A
A/3+26+A+A=180
2A+A/3=154
7A/3=154
7A=462
A=66
B=22
C=92

Answer 2

Let the first angle =∠A =x 
 the second angle = ∠B = 1/3x
and the third angle = ∠C = x + 26°
 ∠A + ∠B + ∠C = 180°
  x + 1/3x + x+26° = 180°
 7x/3 + 26° = 180°
  7x/3 = 180° - 26°
   7x/3 = 154°
  x = 154° x 3/7
 x = 66°
∠A = x= 66°
∠B =1/3 x = 1/3 x 66° = 22°
∠C = x + 26° = 66°+ 26° = 92°