if 3/5 of a number exceeds 1/7 of the same number by 32. find the number.
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Given:-
- 3/5 of a number exceeds 1/7 of the same number by 32.
To find:-
- The number.
Solution:-
Let the required number be x
3/5 of x = 3/5x
1/7 of x = 1/7x
Now, as it is said that 3/5x exceed 1/7x by 32,
Therefore,
3/5x - 1/7x = 32
Taking LCM of 7 and 5
= (21x - 5x)/35 = 32
By cross multiplying,
=> 16x = 32 × 35
=> 16x = 1120
=> x = 1120/16
=> x = 70
Therefore the required number is 70.
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Verification:-
It is said that 3/5 of the number exceeds 1/7 of the same number by 32
It means that if we subtract 3/5 of 70 by 1/7 of 70 then the result must come as 32
Hence,
3/5 of 70 = 3/5 × 70 = 3 × 14 = 42
1/7 of 70 = 1/7 × 70 = 1 × 10 = 10
Now,
The difference:-
42 - 10
= 32
Hence, Verified!
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