Math, asked by rajvaranasi60, 3 months ago

if 3/5 of a number exceeds 1/7 of the same number by 32. find the number. ​

Answers

Answered by samiksha712943
0

Step-by-step explanation:

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Answered by Anonymous
4

Given:-

  • 3/5 of a number exceeds 1/7 of the same number by 32.

To find:-

  • The number.

Solution:-

Let the required number be x

3/5 of x = 3/5x

1/7 of x = 1/7x

Now, as it is said that 3/5x exceed 1/7x by 32,

Therefore,

3/5x - 1/7x = 32

Taking LCM of 7 and 5

= (21x - 5x)/35 = 32

By cross multiplying,

=> 16x = 32 × 35

=> 16x = 1120

=> x = 1120/16

=> x = 70

Therefore the required number is 70.

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Verification:-

It is said that 3/5 of the number exceeds 1/7 of the same number by 32

It means that if we subtract 3/5 of 70 by 1/7 of 70 then the result must come as 32

Hence,

3/5 of 70 = 3/5 × 70 = 3 × 14 = 42

1/7 of 70 = 1/7 × 70 = 1 × 10 = 10

Now,

The difference:-

42 - 10

= 32

Hence, Verified!

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