Question

If 3/5 of a number exceeds its 2/7 by 44, find the number.

Answer 1

Let the number is x.
Then by the given question, 
x×3/5=x×2/7+44
or, 3x/5-2x/7=44
or, (21x-10x)/35=44
or, 11x=44×35
or, x=(44×35)/11
or, x=4×35
or, x=140

Answer 2

Answer:

Required number=$x = 140$

Explanation:

Let the number be x

$\frac{3}{5} \:of \:a \:number = \frac{3x}{5}$

$\frac{2}{7} \:of \:a \:number = \frac{2x}{7}$

According to the problem given,

"3/5 of a number exceeds its 2/7 by 44"

$\frac{3x}{5}-\frac{2x}{7}=44$

$\implies \frac{21x-10x}{35}=44$

$\implies \frac{11x}{35}=44$

$\implies x = 44 \times \frac{35}{11}$

$\implies x = 4 \times 35$

$\implies x = 140$

Therefore,

$x = 140$

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