Question

If (3,- 6) is the mid-point of the line segment joining (0, 0) and (x, y),
then the point (x, y) is
(A) (-3,6)
(B) (6, -6)
(C) (6, -12)
(0) ( 3)​

Answer 1

option (c) is the correct answer ....

use mid point theorem and you will get the answer

hope it will help u ...

Answer 2

The point (x,y) in the line segment is (6,-12)

Step-by-step explanation:

Given that (3,- 6) is the mid-point of the line segment joining (0, 0) and (x, y)

To find the point (x,y) :

• Let $(x_1,y_1)$ and $(x_2,y_2)$ be the given points (0,0) and (x, y)  respectively
• Let M be the mid point of the line segment
• M=(3,-6)

The mid point formula is $M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Now substitute the points in the formula we get

• $(3,-6)=(\frac{0+x}{2},\frac{0+y}{2})$
• $(3,-6)=(\frac{x}{2},\frac{y}{2})$
• Rewritting the above equation
• $(\frac{x}{2},\frac{y}{2})=(3,-6)$

Now equating the x and y values separately

• $\frac{x}{2}=3$ and $\frac{y}{2}=-6$
• $x=3\times 2$ and $y=-6\times 2$
• x=6 and y=-12

Therefore the point (x,y) is (6,-12)

Hence option C) (6,-12) is correct