IF (3+√7)/(3-√7)+(3-√7)/(3+√7) = a+b√7 find the value of a and b
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[(3+√7)/(3-√7) × (3+√7)/(3+√7)] + [(3-√7)/(3+√7) × (3-√7)/(3-√7)]
→ (3+√7)²/(3-√7)(3+√7) + (3-√7)²/(3+√7)(3-√7)
→ [3²+√7²+2(3)(√7)]/(3²-√7²) + [3²+√7²-2(3)(√7)]/(3²-√7²)
→ (9+7+6√7)/(9-7) + (9+7-6√7)/(9-7)
→ [16+6√7+16-6√7)/2
→ 32/2
→ 16
16 = 16+0√7 = a+b√7
a = 16, b = 0
Hope it helps
→ (3+√7)²/(3-√7)(3+√7) + (3-√7)²/(3+√7)(3-√7)
→ [3²+√7²+2(3)(√7)]/(3²-√7²) + [3²+√7²-2(3)(√7)]/(3²-√7²)
→ (9+7+6√7)/(9-7) + (9+7-6√7)/(9-7)
→ [16+6√7+16-6√7)/2
→ 32/2
→ 16
16 = 16+0√7 = a+b√7
a = 16, b = 0
Hope it helps
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