if 3,750 amount to 4,620 in 3 years at
simple interest. Find :
(1) the rate of interest
i) the amount of 7,500 in 5 years at the
same rate of interest
m*
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(i) In first case :
(i) In first case :A = Rs. 4620
(i) In first case :A = Rs. 4620P = Rs. 3750
(i) In first case :A = Rs. 4620P = Rs. 3750I = A – P = Rs. 4620 – Rs. 3750 = Rs. 870
(i) In first case :A = Rs. 4620P = Rs. 3750I = A – P = Rs. 4620 – Rs. 3750 = Rs. 870T = 3 years
(i) In first case :A = Rs. 4620P = Rs. 3750I = A – P = Rs. 4620 – Rs. 3750 = Rs. 870T = 3 yearsR = (100 × I)/(P × T) = (100 × 870)/3750 = (4 × 29)/15
(i) In first case :A = Rs. 4620P = Rs. 3750I = A – P = Rs. 4620 – Rs. 3750 = Rs. 870T = 3 yearsR = (100 × I)/(P × T) = (100 × 870)/3750 = (4 × 29)/15= 116/15 = 7. 11/15%
(i) In first case :A = Rs. 4620P = Rs. 3750I = A – P = Rs. 4620 – Rs. 3750 = Rs. 870T = 3 yearsR = (100 × I)/(P × T) = (100 × 870)/3750 = (4 × 29)/15= 116/15 = 7. 11/15%In Second Case :
(i) In first case :A = Rs. 4620P = Rs. 3750I = A – P = Rs. 4620 – Rs. 3750 = Rs. 870T = 3 yearsR = (100 × I)/(P × T) = (100 × 870)/3750 = (4 × 29)/15= 116/15 = 7. 11/15%In Second Case :P = Rs. 7500
(i) In first case :A = Rs. 4620P = Rs. 3750I = A – P = Rs. 4620 – Rs. 3750 = Rs. 870T = 3 yearsR = (100 × I)/(P × T) = (100 × 870)/3750 = (4 × 29)/15= 116/15 = 7. 11/15%In Second Case :P = Rs. 7500R = 116/15%
(i) In first case :A = Rs. 4620P = Rs. 3750I = A – P = Rs. 4620 – Rs. 3750 = Rs. 870T = 3 yearsR = (100 × I)/(P × T) = (100 × 870)/3750 = (4 × 29)/15= 116/15 = 7. 11/15%In Second Case :P = Rs. 7500R = 116/15%T = 5. ½ years = 11/2 years
(i) In first case :A = Rs. 4620P = Rs. 3750I = A – P = Rs. 4620 – Rs. 3750 = Rs. 870T = 3 yearsR = (100 × I)/(P × T) = (100 × 870)/3750 = (4 × 29)/15= 116/15 = 7. 11/15%In Second Case :P = Rs. 7500R = 116/15%T = 5. ½ years = 11/2 yearsInterest = (P × T × R)/100
(i) In first case :A = Rs. 4620P = Rs. 3750I = A – P = Rs. 4620 – Rs. 3750 = Rs. 870T = 3 yearsR = (100 × I)/(P × T) = (100 × 870)/3750 = (4 × 29)/15= 116/15 = 7. 11/15%In Second Case :P = Rs. 7500R = 116/15%T = 5. ½ years = 11/2 yearsInterest = (P × T × R)/100= Rs. (7500 × 11 × 116)/(2 × 15 × 100) = (250 × 116 × 11)/100
(i) In first case :A = Rs. 4620P = Rs. 3750I = A – P = Rs. 4620 – Rs. 3750 = Rs. 870T = 3 yearsR = (100 × I)/(P × T) = (100 × 870)/3750 = (4 × 29)/15= 116/15 = 7. 11/15%In Second Case :P = Rs. 7500R = 116/15%T = 5. ½ years = 11/2 yearsInterest = (P × T × R)/100= Rs. (7500 × 11 × 116)/(2 × 15 × 100) = (250 × 116 × 11)/100= 10 × 29 × 11 = 290 × 11 = Rs. 3190
(i) In first case :A = Rs. 4620P = Rs. 3750I = A – P = Rs. 4620 – Rs. 3750 = Rs. 870T = 3 yearsR = (100 × I)/(P × T) = (100 × 870)/3750 = (4 × 29)/15= 116/15 = 7. 11/15%In Second Case :P = Rs. 7500R = 116/15%T = 5. ½ years = 11/2 yearsInterest = (P × T × R)/100= Rs. (7500 × 11 × 116)/(2 × 15 × 100) = (250 × 116 × 11)/100= 10 × 29 × 11 = 290 × 11 = Rs. 3190Amount = Rs. 7500 + 3190 = Rs. 10,690
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