Question

If -3,a,2 are three consecutive terms of an a.p than find a?

Answer 1

Answer:

Step-by-step explanation:

difference of all will be same So D equals to a - 3D equals to-3

A + 3D equals to 2 then from this D equals to 5 by 6. therefore A equals to 7/6.

Answer 2

Here is your answer-

let,
The three consecutive terrms of A.P. are -3, a, 2.

So,
t1 = -3
t2 = a
t3 = 2
d = a - (-3) = a + 3
n = 3


By general formula for tn

tn = t1 + (n - 1) d
t3 = -3 + ( 3-1) (a+3)
2 = -3 + 2(a+3)
2 = -3 + 2a + 6
2a = 2+3-6
2a = -1
a = -1/2
a = -0.5

Therefore,
d = a + 3
d = -0.5 + 3
d = 2.5

Verify,
d = t2-t1 = -0.5- 3 = 2.5
d = t3-t2 = 2-(-0.5) = 2+0.5 = 2.5

So,
the value of a is -0.5

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