if 3^a =4^b=12^c then show that c=ab/a+b
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- 3^a =4^b=12^c= k
- 3^a= k ⇒ 3= k^1/a
- 4^b=k ⇒ 4= k^1/b
12^c=k
12^c=3^c*4^c= k^c/a*k^c/b= k^(c/a+c/b)
k= k^(c/a+c/b)
- c/a+c/b=1
- c(a+b)=ab
- c= ab/(a+b)
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