Question

The difference of two natural number is 3 and their squares have the sum 117 then the number is:
A. 6
B.9
C.-6
D.-9

Answer 1

Answer:

The difference of two natural number is 3 and their squares have the sum 117 then the number is:

A. 6

B.9

C.-6

D.-9

Can be 9 and 6 . both option A & B

Answer 2

Answer:

X=9 , y=6

Step-by-step explanation:

Let natural no. Be

X and y

So

A/q

Difference of them = 3

So,

X-y= 3

X= 3+y

So

Then

There squares have sum 117

So,

X²+y²= 117

(3+y)²+y²=117

9+y²+6y+y²=117

2y²+6y=117-9

2y²+6y-108=0

2y²+(18-12)y-108=0

2y²+18y-12y-108=0

2y(y+9) -12(y+9) =0

(2y-12) (y-9) = 0

2y-12=0 y+9=0

Y=6 y= -9

So,

Y= 6

X-y=3

X-6=3

X=9