Question

if -3 and 2 are roots of equation x×x-{p+2}x-q=0 find p and q

Answer 1

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Answer 2

p(x) = x^2 - (p+2)x - q 
p(-3) = (-3)^2 - (p+2)(-3) - q
         = 9 + 3p + 6 - q 
         = 3p - q + 15                       ..................(1)

p(2)  = 2^2 - (p + 2)2 - q 
        = 4 -2p - 4 -q 
        = -2p - q                     .......................(2)   
 
 from 1 and 2
          p = -3 and q = 6