Question

If 3 and -3 are the solutions of equation ax^2 + bx - 9 = 0; find the values of a and b. ​

Answer 1

Answer:

heya mate there's your answer

if ax^2+bx+c=0 is a quadratic equation then, sum of roots =-b/a

Product of roots =c/a

so on comparing a =a, b=b ,c=-9

sum of roots =3-3=-b/a

b/a=0____________(1)

product of roots =3×-3=-9=c/a

-9/a=-9

1/a=1

a=1

from (1) b/a =0

b/1=0

b=0

so a =1 and b=0

hope it helps you

Thank you

Answer 2

Answer:

a=1, b=0

Step-by-step explanation:

putting x=3 in the given equation

9a + 3b - 9 =0.....(i)

putting x=-3

9a -3b - 9 =0.....(ii)

adding (i)+(ii),

18a = 18

so, a = 1

putting a=1 in any of the above equations you get b=0