Question

If 3 and minus 3 or 2 zeros of the polynomial x 4 + x cube minus 11 x square - 9 X + 18 find all the zeros of the given polynomial

Answer 1

divide the polynomial by x^2-9

Answer 2

3 & -3 are zeros of polynomial
then X^4 + X^3 - 11X^2 -9X +18 divided by (X-3)(X+3)

(X^4 + X^3 - 11X^2 -9X +18)/(X-3)(X+3)
then you got a quoitent as quadratic
solve it and got two other zeros.