If 3 cos 0 = 1, then find the value of cosec 0.
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Cos 0=1/3 (adjacent of 0/ hypotenuse )
By Pythagorean’s theorem
3^2= 1+x^2
9-1=x^2
(8)^1/2 = x
Cosec 0= hypotenuse / side opposite to 0 = 3/v8
By Pythagorean’s theorem
3^2= 1+x^2
9-1=x^2
(8)^1/2 = x
Cosec 0= hypotenuse / side opposite to 0 = 3/v8
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