Question

If 3 costheta =2sintheta find 4 sintheta-3 costheta/2 sintheta +6costheta​

Answer 1

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For first excited state n = 2.

so V = (2.18 x {{10}^{6}})/2 m/s.

time period = 2 π R°/ V.

(radius taken for orbital n=2)

R° = n²r ( r =52.9 pm)

so T = 2× 2² ×52.9 ×10-¹²/ 1.09 x {{10}^{6}}

T =1.22 × 10^-15 seconds....

Answer 2

Answer:

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