If 3 cot θ = 2, find the value of 4sin????-3cos???? / 2sin????+ 6cos????
Answers
Answered by
0
4sinθ-3cosθ / 2sinθ+ 6cosθ = 1/3
Step-by-step explanation:
Given: 3 cot θ = 2
To find: value of 4sinθ-3cosθ / 2sinθ+ 6cosθ
Solution:
3 cot θ = 2
Cot θ = 2/3
Cos θ / Sin θ = 2/3
Cos θ = 2Sinθ/3
Now, 4sinθ-3cosθ / 2sinθ+ 6cosθ = 4Sinθ-3(2Sinθ/3)/ 2sinθ+ 6(2Sinθ/3)
= 4Sinθ - 2Sinθ / 2Sinθ + 4Sinθ
= 2(2Sinθ - Sinθ) / 2(Sinθ + 2Sinθ)
= Sinθ / 3Sinθ
= 1/3
Value of 4sinθ-3cosθ / 2sinθ+ 6cosθ = 1/3
Similar questions