if 3 cot a equal to 2 then find the value of 4 Sin A-3 Cos A divided by 2 Sin A + 3 Co SA
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Answer:
cot A = 2/3
by Pythagoras,
cot a = b/p = 2/3
hypotenuse = √13
sin A = p/h = 3/√13
cos A = b/h = 2/√13
putting the value in the eq.
4*3/√13 - 3* 2/√13/ 2*3/√13 + 3*2/√13
12/√13 - 6/√13 / 6/√13 + 6/√13
12-6/√13 / 6+6/√13
6/√13 * √13/ 12
answer is 1/2
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