Question

If 3 cotA = 2 , then find the value of 4 sinA - 3 cosA / 2sinA + 2 cos A

Answer 1

Answer:

3cotA=2

cotA=2/3=b/p

b=2,p=3

Then,h=√(2)²+(3)²=√4+9=√13

Then,sinA=p/h=3/√13

cosA=b/h=2/√13

Now,we solve the problem,

4sinA-3cosA/2sinA+2cosA

(4×3/√13-3×2/√13)/(2×3/√13+2×2/√13)

(12/√13-6/√13)/(6/√13+4/√13)

(12-6/√13)/(6+4/√13)

(6/√13)/(10/√13)

6×√13/√13×10

6/10

3/5

Step-by-step explanation: