Question

if 3 is a root of 2x^2+Kx+4=0 then k =?​

Answer 1

Answer:

given one root is 3

let other root be'a'

sum of roots=3+a=-k /2

product of roots=3a=4/2=2

a=2/3

sum=3+2/3=11/3

11/3=-K/2

K=-22/3

Answer 2

Answer:

If 3 is a root of 2x^2 + kx + 4, then k = -22/3

Step-by-step explanation:

Let p(x) = 2x^2 + kx + 4

It is given that the root of p(x) is 3

Therefore, p(3) = 2(3)^2 + k(3) + 4 = 0

2×9 + 3k + 4 = 0

18 + 3k + 4 = 0

3k + 22 = 0

3k = -22

k = -22/3