Math, asked by hemraj274200497, 11 months ago

If 3 is a solution of 3x² + (k-1)x + 9 = 0 then the value of k is ?​

Answers

Answered by tanugoyanka
5

Answer:

3 (3)^2+(k-1)3+9=0

27+3k-3+9=0

33+3k=0

3k=(-33)

k=(-11)

Answered by ProSaurav
1

Answer:

The value of k is (-11).

Step-by-step explanation:

If 3 is a solution of the given equation, then x can be equal to 3.

Substituting,

=> 3*(3)^2 + (k-1)*(3) + 9 = 0

=> 27+9+3k-3=0 {Opening brackets}

=> 33+3k=0 {Adding}

=> 3*(11+k)=0 {Taking 3 common}

=> k+11=0 {0/3=0}

=> k=(-11)


hemraj274200497: hi
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