Question

if 3 is a zero of polynomial y^2-3y-2k then find the value of k

Answer 1

Answer:

k=0

Step-by-step explanation:

given that y=3

${3}^{2} - 3 \times 3 - 2k = 9 - 9 - 2k \\ 0 - 2k = 0 \\ - 2k = 0 \\ k = 0 \div - 2 = 0$