If -3 is a zero of the polynomial x2+ x - (3 + 2k) then find the value of k
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Given :
-3 , is zero of x² + x - (3 + 2k)
To find : k
Property used :
If , "y" is zero of polynomial p(x) = ax² + bx + c. Therefore p(y) will be equal to zero
Steps to follow :
- First of all put x = -3
- Then put p(-3) = 0
- Solve for k
Solution :
Let , x² + x - (3+2k) = p(x)
If x = -3 is zero of polynomial, then p(-3) = 0
p(-3) = (-3)² + (-3) - (3+2k)
0 = 9 - 3 - (3+2k)
0 = 6 - 3 - 2k
2k = 3
k = 3/2
ANSWER :
k = (3/2)
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