if 3 is added to the numerator the fraction becomes 2/3 .the original fraction has numerator less
by 6 than the denominator
find the fraction
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let numerator is x and denominator is y
fraction = x/y
according to question
x = y-6 -----------------(1)
(x+3)/y = 2/3
3x+9 = 2y ------------------------(2)
(2) - 2×(1)
x+9 = 12
x = 3
put the value of x in equation (1)
y = 6+3 = 9
fraction = 3/9 = 1/3
fraction = x/y
according to question
x = y-6 -----------------(1)
(x+3)/y = 2/3
3x+9 = 2y ------------------------(2)
(2) - 2×(1)
x+9 = 12
x = 3
put the value of x in equation (1)
y = 6+3 = 9
fraction = 3/9 = 1/3
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