If -3 is on of the zeroes of the polynomial (k-1)x^2+kx+1, find the value of k
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prathampc:
It was +1
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Answered by
2
-3 is one zero of the eq
so
(k-1)(-3)^2+k (-3)+1=0
9k-9-3k+1=0
6k-8=0
6k=8
k=8/6
k=4/3
that's it...
hope it will help you
so
(k-1)(-3)^2+k (-3)+1=0
9k-9-3k+1=0
6k-8=0
6k=8
k=8/6
k=4/3
that's it...
hope it will help you
sorry i did a mistake
Yes better edit it
k=8/6
sis pls edit ur ans
Np I understood
Thanks
okk..done..:)
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