Question

if -3 is one of the o of the polynomial (k-1)x2+kx+1 find the value of k

Answer 1

Hi there!

Given eqn. (k-1)x² + kx + 1 = 0

(k-1)(-3)² + k(-3) + 1 = 0

9k - 9 - 3k + 1 = 0

6k - 8 = 0

k = 8/6

k = 4/3

Hope it helps! :D

Answer 2

Hey there!
Down here ⏬


> if -3 is one of the o of the polynomial p(x) (k-1)x2+kx+1 find the value of k


-3 is the zero of p(x)
which means, p(-3) = 0.


$(k - 1) \: ( - 3){}^{2} + k( - 3) + 1 = 0$


$9(k - 1) - 3k + 1 = 0$


$9k - 9 - 3k + 1 = 0$

$6k - 8 = 0$

$6k = 8$

$k = \frac{8}{6}$

$k = \frac{3}{4}$

Glad if helped <3