Question

If -3 is one of the zero of the polynomial (k-1)x^2+kx+1, Find the value of k

Answer 1

Putting x=-3 in (k-1)x²+kx+1
(k-1)x²+kx+1=0
(k-1)(-3)²+k(-3)+1=0
(k-1)(9)-3k+1=0
9k-9-3k+1=0
6k-8=0
k=8/6
k=4/3

Answer 2

(k-1)x^2+kx+1=0is given polynomial
Just put the value of X in given polynomial
(k-1)(-3)^2+k(-3)+1=0
Now, (k-1)(9)-3k+1=0
9k-9-3k+1=0
9k-3k-9+1=0
6k-8=0
6k=8
k=8/6
k=4/3
hope it helps u!