Question

If -3 is one of the zero of the quadric polynomial (k-1)x2+kx-3 , find the value of k

Answer 1

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Value of k = 2

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Polynomial p(x) = (k - 1)x² + kx - 3

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Value of k.

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We are given that -3 is a zero of the polynomial p(x).

∴ p(-3) = 0

Now, substituting the value in the equation we get,

⇝ (k - 1)(-3)² + k(-3) - 3 = 0

⇝ (k - 1)9 - 3k - 3 = 0

⇝ 9k - 9 - 3k - 3 = 0

⇝ 6k - 12 = 0

⇝ 6k = 12

⇝ k = 12/6

⇝ k = 2

Hence, the value of k is 2.