Question

If -3 is one of the zeros of the quadratic polynomial (k-1)x2+kx-3,than the value of k is

Answer 1

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If -3 is one of the zeros of the quadratic polynomial (k-1)x2+kx-3,than the value of k is

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=>if x-3 is a one of the zeroes of the polynomial then then the value of x be 3 (x-3=0).

=>now , put this value in above equation to find out the value of k:-

$= > {(k - 1)x}^{2} +k x - 3 = 0$

$= > (k - 1) {3}^{2} + k(3) - 3 = 0$

$= > (k - 1)9 + 3k - 3 = 0$

$= > 9k - 9 + 3k - 3 = 0$

$= > 12k - 12 = 0$

$= > 12k = 12$

$\boxed{\red{= >k = 1}}$

Now,put the value of k in equation to check :-

$= > (1 - 1)9 + 3(1) - 3 = 0$

$= > 9 \times 0 + 3 - 3 = 0$

$= > 0 + 0 = 0$

$= > 0 = 0$

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Answer 2

Answer:

The zeros of the polynomial is -3 .

Step-by-step explanation:

(k-1) x²+Kx-3

= (k-1) (-3)²+ k× (-3) -3=0

= (k-1)9-3k-3 =0

= 9k-9 -3k-3 =0

= 6k -6 =0

= 6k=6

=k= 1