Question

if -3 is root of quadratic equation x^2 + mx - 3 = 0 and x^2 + mx + n = 0 has equal roots, then the value of n is

Answer 1

Answer:

we replace x by -3 in eq1

p(-3)=(-3)²+m(-3)-3

=9-3m-3=0

6-3m=0

-3m=-6

m=-6/-3

m=2

we replace m by 2 and x by -3 in eq2

p(-3)=(-3)² +2(-3)+n=0

9-6+n=0

3+n=0

n=-3

therefore,

m=2 and n=-3