Question

if 3 is the root of equation 7x^2 -(k+1) x+3 =0 , then value of k​

Answer 1

Answer:

k=21

Step-by-step explanation:

p(x)=7x^2-(k+1)x+3=0

p(3)=7(3)^2-(k+1)*3+3=0

7(9)-3k-3+3=0

63-3k=0

-3k=-63

3k=63

k=63/3

k=21

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Answer 2

ANSWER IS :-

K=12

HOPE IT HELPS YOU