Question

if 3.n(n-1) = 330 find n3​

Answer 1

Step-by-step explanation:

3n (n-1) = 330

or n(n-1) = 330/3

or n²-n = 110

or n²-n -110= 0

or, n²-(11-10)n -110=0

or, n²-11n+10n-110= 0

or, n(n-11)+10(n-11)= 0

or, (n-11)(n+10)= 0

either n-11=0 or n+10=0

or n=11. => n=-10 ( can not n value -10 because it doesn't follow above the equation)

so value of. n= 11

so n³= 11³ = 1331