if 3+root2 /root3-roor2 =a+b root6, find the value of a and b
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Step-by-step explanation:
3+root2/root3-root2
rationalise the denominator
(3+root2)(root3+root2)/(root3)2-(root2)2
3root3+3root2-root6+root4
(2+3root3+3root2)-root6
a=(2+3root3+3root2
b=-1
Answered by
1
Answer:
Hope the answer is helpful
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