if √3 sec theta = √6 find I) theta. ii) sin ^2 theta - cos ^2 theta iii) cot ^2 theta - cosec ^2 theta
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Answer:
Correct option is
D
4
3
tanθ=
7
1
⇒cotθ=
7
∴sec
2
θ=(1+tan
2
θ)=1+
7
1
=
7
8
and cosec
2
θ=(1+cot
2
θ)=1+7=8.
∴
cosec
2
θ+sec
2
θ
cosec
2
θ−sec
2
θ
=
8+
7
8
8−
7
8
=
64
48
=
4
3
.
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