If 3 Sin A - 4 Cos A = 0. then the value of tan A =
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solution
3sinФ - 4cosФ=0
3sinФ=4cosФ
⇒ sinФ/cosФ=4/3
⇒ tanФ=4/3
⇒ tanФ=4/3
then the value of
tanФ=4/3
for 1 + tan²Ф=sec²Ф
⇒ 1 + 4/3=sec²Ф
⇒√ (3+4)/3=secФ
⇒ secФ=√7/3
for cosec²Ф=cot²Ф+1
⇒cosec²Ф=3/4+1
cosecФ=√7/4
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--> 3Sin A - 4Cos A = 0
--> 3Sin A = 4Cos A
--> tan A = Sin A / Cos A = 4/3
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