Question

If √3 sinQ-cosQ=0 and 0°

Answer 1

Answer: 30 degree

Step-by-step explanation:

I suppose you want to find <Q

so,

$\sqrt3sinQ-cosQ=0\\=>-cosQ=-\sqrt3sinQ\\=>cosQ=\sqrt3sinQ\\ \\ =>\frac{sinQ}{cosQ}=\frac{1}{\sqrt3}\\=>tanQ=\frac{1}{\sqrt3}\\but\;\;tan30=\frac{1}{\sqrt3}\\ \\ => <Q=30degree$

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