Question

If 3 tanθ = 4 ; then evaluate

3 sin

θ

+

2cos

θ ÷

3 sin

θ

−

2

cos

θ​

Answer 1

Answer:

v

Step-by-step explanation:

3 tan θ=4

tan θ=4/3

w.k.t sin θ/cos θ=tan θ

therefore sin θ=4

cos θ=3

Answer 2

Answer:

3 tan theta= 4

tan theta=4/3

p/b=4/3

By using Pythagoras theorem, we get

p^2 + b^2=h^2

(4)^2+(3)^2=h^2

16+9=h^2

25=h^2

h=root 25

=5

Now,

3sin theta + 2cos theta÷3sin theta - 2cos theta

=3×p/h +2×b/h÷3×p/h - 2×b/h

=3×4/5+2×3/5÷3×4/5-2×3/5

=12/5+6/5÷12/5-6/5

=18/5÷6/5

=18/5×5/6 ( since 18 is cancelled by 6

and 5 is cancelled by 5)

.

. . Answer of this question is 3.