if √3 tan Ø=3, then find value of sin²Ø=cos²Ø.
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Answer:
1/3=1/9
Step-by-step explanation:
tanQ=√3
p=√3,b=1 so H =3
(√3)^2/(3)^2=(1)^2/(3)^2
3/9=1/9
1/3=1/9
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