Question

If 3 tan q = 3 sin q, (q ≠ 0) then the value of sin2 q – cos2 q is

Answer 1

Answer:

√3sinq/cosq=3 sinq

secq=√3

cosq=1/√3

cos²q=1/3

sin²q+cos²q=1-cos²q-cos²q=1-2cos²q...........[sin²q=1-cos²q]

1-2(1/3)=1-2/3

=1/3

hope it helps you