x3-6x2+11x-6= 0 হলে x =?
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Answer:
x^3–6x^2+11x-6
=x^3-x^2–5x^2+5x+6x-6
=x^2(x-1)-5x(x-1)+6(x-1)
=(x-1)(x^2–5x+6)
=(x-1)(x^2–2x-3x+6)
=(x-1){x(x-2)-3(x-2)}
=(x-1){(x-2)(x-3)}
=(x-1)(x-2)(x-3)
From Q., (x-1)(x-2)(x-3)=0
Thus, x=1,2,3
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