Math, asked by rakesh5612, 1 year ago

If 3 tan X-5 cos y=√3, and y= 90°, find the value of x.​

Answers

Answered by ihrishi
1

Answer:

3 \: tanx - 5 \: cosy =  \sqrt{3}  \\  \therefore \: 3 \: tanx - 5 \: cos \: 90 \degree =  \sqrt{3} \\ ( \because \: y  =90 \degree) \\ \therefore \: 3 \: tanx - 5  \times 0 =  \sqrt{3} \\ ( \because \:cos \: 90 \degree = 0) \\ \therefore \: 3 \: tanx - 0=  \sqrt{3} \\\therefore \: 3 \: tanx =  \sqrt{3} \\ \implies \: tanx =  \frac{ \sqrt{3} }{3}  \\  \implies \: tanx =  \frac{ \sqrt{3} }{\sqrt{3}  \times \sqrt{3} }  \\ \implies \: tanx =  \frac{ 1}{\sqrt{3} }  \\ \implies \: tanx = tan \: 30 \degree \\ \implies \: \huge \fbox{ x = 30 \degree } \\

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