If 3 tanA=4 then find sinA and cosA
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Answer:
sinA=4/5
cosA=3/5
Step-by-step explanation:
3 tan A = 4
therefore, tanA= 4/3
tan A = opposite side/ adjacent side
AC² = AB² + BC²
= 4² + 3²
= 16 + 9
= 25
therefore AC = root25
= 5
sinA = opposite/ hypotenuse = 4/5
cosA = adjacent/hypotenuse = 3/5
Hope this helps :)
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